两角和公式:sjB
sin(A+B)=sinAcosB+cosAsinBsin(A-B)=sinAcosB-sinBcosAb d s h 5 c o m
cos(A+B)=cosAcosB-sinAsinBcos(A-B)=cosAcosB+sinAsinB来自www.bdsh5.com
tan(A+B)=(tanA+tanB)/(1-tanAtanB)tan(A-B)=(tanA-tanB)/(1+tanAtanB)b.d.s.h.5.c.o.m
ctg(A+B)=(ctgActgB-1)/(ctgB+ctgA)ctg(A-B)=(ctgActgB+1)/(ctgB-ctgA)b_d_s_h_5_c_o_m
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